(2y-6)+20=-30

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Solution for (2y-6)+20=-30 equation: 



(2y-6)+20=-30

We move all terms to the left:

(2y-6)+20-(-30)=0

We add all the numbers together, and all the variables

(2y-6)+50=0

We get rid of parentheses

2y-6+50=0

We add all the numbers together, and all the variables

2y+44=0

We move all terms containing y to the left, all other terms to the right

2y=-44

y=-44/2

y=-22

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