(2y-6)+20=30

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Solution for (2y-6)+20=30 equation: 



(2y-6)+20=30

We move all terms to the left:

(2y-6)+20-(30)=0

We add all the numbers together, and all the variables

(2y-6)-10=0

We get rid of parentheses

2y-6-10=0

We add all the numbers together, and all the variables

2y-16=0

We move all terms containing y to the left, all other terms to the right

2y=16

y=16/2

y=8

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