(2y-7)+8(y+6)=31

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Solution for (2y-7)+8(y+6)=31 equation: 



(2y-7)+8(y+6)=31

We move all terms to the left:

(2y-7)+8(y+6)-(31)=0

We multiply parentheses

(2y-7)+8y+48-31=0

We get rid of parentheses

2y+8y-7+48-31=0

We add all the numbers together, and all the variables

10y+10=0

We move all terms containing y to the left, all other terms to the right

10y=-10

y=-10/10

y=-1

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