(2y-8)-3(4-3y)=11y-20

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Solution for (2y-8)-3(4-3y)=11y-20 equation: 


Simplifying
(2y + -8) + -3(4 + -3y) = 11y + -20

Reorder the terms:
(-8 + 2y) + -3(4 + -3y) = 11y + -20

Remove parenthesis around (-8 + 2y)
-8 + 2y + -3(4 + -3y) = 11y + -20
-8 + 2y + (4 * -3 + -3y * -3) = 11y + -20
-8 + 2y + (-12 + 9y) = 11y + -20

Reorder the terms:
-8 + -12 + 2y + 9y = 11y + -20

Combine like terms: -8 + -12 = -20
-20 + 2y + 9y = 11y + -20

Combine like terms: 2y + 9y = 11y
-20 + 11y = 11y + -20

Reorder the terms:
-20 + 11y = -20 + 11y

Add '20' to each side of the equation.
-20 + 20 + 11y = -20 + 20 + 11y

Combine like terms: -20 + 20 = 0
0 + 11y = -20 + 20 + 11y
11y = -20 + 20 + 11y

Combine like terms: -20 + 20 = 0
11y = 0 + 11y
11y = 11y

Add '-11y' to each side of the equation.
11y + -11y = 11y + -11y

Combine like terms: 11y + -11y = 0
0 = 11y + -11y

Combine like terms: 11y + -11y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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