(2y-8)=(3y-2)

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Solution for (2y-8)=(3y-2) equation: 



(2y-8)=(3y-2)

We move all terms to the left:

(2y-8)-((3y-2))=0

We get rid of parentheses

2y-((3y-2))-8=0



We calculate terms in parentheses: -((3y-2)), so:

(3y-2)

We get rid of parentheses

3y-2

Back to the equation:

-(3y-2)



We get rid of parentheses

2y-3y+2-8=0

We add all the numbers together, and all the variables

-1y-6=0

We move all terms containing y to the left, all other terms to the right

-y=6

y=6/-1

y=-6

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