(2y/3)-(3/4)=(1/12)

Solution for (2y/3)-(3/4)=(1/12) equation:

(2y/3)-(3/4)=(1/12)

We move all terms to the left:

(2y/3)-(3/4)-((1/12))=0

We add all the numbers together, and all the variables

(+2y/3)-(+3/4)-((+1/12))=0

We get rid of parentheses

2y/3-3/4-((+1/12))=0

We calculate fractions


96y^2/()+()/()+()/()=0

We add all the numbers together, and all the variables

96y^2/()+2=0

We multiply all the terms by the denominator


96y^2+2*()=0

We add all the numbers together, and all the variables

96y^2=0

a = 96; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·96·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{192}=0$