(2z+1)(6+z)=0

Solution for (2z+1)(6+z)=0 equation:

Simplifying
(2z + 1)(6 + z) = 0

Reorder the terms:
(1 + 2z)(6 + z) = 0

Multiply (1 + 2z) * (6 + z)
(1(6 + z) + 2z * (6 + z)) = 0
((6 * 1 + z * 1) + 2z * (6 + z)) = 0
((6 + 1z) + 2z * (6 + z)) = 0
(6 + 1z + (6 * 2z + z * 2z)) = 0
(6 + 1z + (12z + 2z2)) = 0

Combine like terms: 1z + 12z = 13z
(6 + 13z + 2z2) = 0

Solving
6 + 13z + 2z2 = 0

Solving for variable 'z'.

Factor a trinomial.
(6 + z)(1 + 2z) = 0

Subproblem 1
Set the factor '(6 + z)' equal to zero and attempt to solve:

Simplifying
6 + z = 0

Solving
6 + z = 0

Move all terms containing z to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + z = 0 + -6

Combine like terms: 6 + -6 = 0
0 + z = 0 + -6
z = 0 + -6

Combine like terms: 0 + -6 = -6
z = -6

Simplifying
z = -6
Subproblem 2
Set the factor '(1 + 2z)' equal to zero and attempt to solve:

Simplifying
1 + 2z = 0

Solving
1 + 2z = 0

Move all terms containing z to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 2z = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 2z = 0 + -1
2z = 0 + -1

Combine like terms: 0 + -1 = -1
2z = -1

Divide each side by '2'.
z = -0.5

Simplifying
z = -0.5
Solution
z = {-6, -0.5}