(2z+1)=(7z+2)

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Solution for (2z+1)=(7z+2) equation: 



(2z+1)=(7z+2)

We move all terms to the left:

(2z+1)-((7z+2))=0

We get rid of parentheses

2z-((7z+2))+1=0



We calculate terms in parentheses: -((7z+2)), so:

(7z+2)

We get rid of parentheses

7z+2

Back to the equation:

-(7z+2)



We get rid of parentheses

2z-7z-2+1=0

We add all the numbers together, and all the variables

-5z-1=0

We move all terms containing z to the left, all other terms to the right

-5z=1

z=1/-5

z=-1/5

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