(2z+3)6=96

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Solution for (2z+3)6=96 equation: 



(2z+3)6=96

We move all terms to the left:

(2z+3)6-(96)=0

We multiply parentheses

12z+18-96=0

We add all the numbers together, and all the variables

12z-78=0

We move all terms containing z to the left, all other terms to the right

12z=78

z=78/12

z=6+1/2

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