(2z+6)+(4z-3)=(5z+13)

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Solution for (2z+6)+(4z-3)=(5z+13) equation: 



(2z+6)+(4z-3)=(5z+13)

We move all terms to the left:

(2z+6)+(4z-3)-((5z+13))=0

We get rid of parentheses

2z+4z-((5z+13))+6-3=0



We calculate terms in parentheses: -((5z+13)), so:

(5z+13)

We get rid of parentheses

5z+13

Back to the equation:

-(5z+13)



We add all the numbers together, and all the variables

6z-(5z+13)+3=0

We get rid of parentheses

6z-5z-13+3=0

We add all the numbers together, and all the variables

z-10=0

We move all terms containing z to the left, all other terms to the right

z=10

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