(2z+6)=(4z-3)=(5z+12)

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Solution for (2z+6)=(4z-3)=(5z+12) equation:



(2z+6)=(4z-3)=(5z+12)
We move all terms to the left:
(2z+6)-((4z-3))=0
We get rid of parentheses
2z-((4z-3))+6=0
We calculate terms in parentheses: -((4z-3)), so:
(4z-3)
We get rid of parentheses
4z-3
Back to the equation:
-(4z-3)
We get rid of parentheses
2z-4z+3+6=0
We add all the numbers together, and all the variables
-2z+9=0
We move all terms containing z to the left, all other terms to the right
-2z=-9
z=-9/-2
z=4+1/2

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