(2z+6)=(4z-3)=(5z+12)

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Solution for (2z+6)=(4z-3)=(5z+12) equation: 



(2z+6)=(4z-3)=(5z+12)

We move all terms to the left:

(2z+6)-((4z-3))=0

We get rid of parentheses

2z-((4z-3))+6=0



We calculate terms in parentheses: -((4z-3)), so:

(4z-3)

We get rid of parentheses

4z-3

Back to the equation:

-(4z-3)



We get rid of parentheses

2z-4z+3+6=0

We add all the numbers together, and all the variables

-2z+9=0

We move all terms containing z to the left, all other terms to the right

-2z=-9

z=-9/-2

z=4+1/2

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