(2z+7)(3)=49

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Solution for (2z+7)(3)=49 equation:



(2z+7)(3)=49
We move all terms to the left:
(2z+7)(3)-(49)=0
We multiply parentheses
6z+21-49=0
We add all the numbers together, and all the variables
6z-28=0
We move all terms containing z to the left, all other terms to the right
6z=28
z=28/6
z=4+2/3

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