(2z+7)(3)=49

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Solution for (2z+7)(3)=49 equation: 



(2z+7)(3)=49

We move all terms to the left:

(2z+7)(3)-(49)=0

We multiply parentheses

6z+21-49=0

We add all the numbers together, and all the variables

6z-28=0

We move all terms containing z to the left, all other terms to the right

6z=28

z=28/6

z=4+2/3

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