(2z+8)+(7z+3)=65

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Solution for (2z+8)+(7z+3)=65 equation:


Simplifying
(2z + 8) + (7z + 3) = 65

Reorder the terms:
(8 + 2z) + (7z + 3) = 65

Remove parenthesis around (8 + 2z)
8 + 2z + (7z + 3) = 65

Reorder the terms:
8 + 2z + (3 + 7z) = 65

Remove parenthesis around (3 + 7z)
8 + 2z + 3 + 7z = 65

Reorder the terms:
8 + 3 + 2z + 7z = 65

Combine like terms: 8 + 3 = 11
11 + 2z + 7z = 65

Combine like terms: 2z + 7z = 9z
11 + 9z = 65

Solving
11 + 9z = 65

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-11' to each side of the equation.
11 + -11 + 9z = 65 + -11

Combine like terms: 11 + -11 = 0
0 + 9z = 65 + -11
9z = 65 + -11

Combine like terms: 65 + -11 = 54
9z = 54

Divide each side by '9'.
z = 6

Simplifying
z = 6

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