(2z+9)=(4z-3)

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Solution for (2z+9)=(4z-3) equation: 



(2z+9)=(4z-3)

We move all terms to the left:

(2z+9)-((4z-3))=0

We get rid of parentheses

2z-((4z-3))+9=0



We calculate terms in parentheses: -((4z-3)), so:

(4z-3)

We get rid of parentheses

4z-3

Back to the equation:

-(4z-3)



We get rid of parentheses

2z-4z+3+9=0

We add all the numbers together, and all the variables

-2z+12=0

We move all terms containing z to the left, all other terms to the right

-2z=-12

z=-12/-2

z=+6

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