(2z+92)=(3z+95)

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Solution for (2z+92)=(3z+95) equation: 



(2z+92)=(3z+95)

We move all terms to the left:

(2z+92)-((3z+95))=0

We get rid of parentheses

2z-((3z+95))+92=0



We calculate terms in parentheses: -((3z+95)), so:

(3z+95)

We get rid of parentheses

3z+95

Back to the equation:

-(3z+95)



We get rid of parentheses

2z-3z-95+92=0

We add all the numbers together, and all the variables

-1z-3=0

We move all terms containing z to the left, all other terms to the right

-z=3

z=3/-1

z=-3

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