(2z-1)(2z+1)=

Solution for (2z-1)(2z+1)= equation:

Simplifying
(2z + -1)(2z + 1) = 0

Reorder the terms:
(-1 + 2z)(2z + 1) = 0

Reorder the terms:
(-1 + 2z)(1 + 2z) = 0

Multiply (-1 + 2z) * (1 + 2z)
(-1(1 + 2z) + 2z * (1 + 2z)) = 0
((1 * -1 + 2z * -1) + 2z * (1 + 2z)) = 0
((-1 + -2z) + 2z * (1 + 2z)) = 0
(-1 + -2z + (1 * 2z + 2z * 2z)) = 0
(-1 + -2z + (2z + 4z2)) = 0

Combine like terms: -2z + 2z = 0
(-1 + 0 + 4z2) = 0
(-1 + 4z2) = 0

Solving
-1 + 4z2 = 0

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 4z2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 4z2 = 0 + 1
4z2 = 0 + 1

Combine like terms: 0 + 1 = 1
4z2 = 1

Divide each side by '4'.
z2 = 0.25

Simplifying
z2 = 0.25

Take the square root of each side:
z = {-0.5, 0.5}