(2z-100)+z=(z+50)+(2z-100)-20

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Solution for (2z-100)+z=(z+50)+(2z-100)-20 equation:


Simplifying
(2z + -100) + z = (z + 50) + (2z + -100) + -20

Reorder the terms:
(-100 + 2z) + z = (z + 50) + (2z + -100) + -20

Remove parenthesis around (-100 + 2z)
-100 + 2z + z = (z + 50) + (2z + -100) + -20

Combine like terms: 2z + z = 3z
-100 + 3z = (z + 50) + (2z + -100) + -20

Reorder the terms:
-100 + 3z = (50 + z) + (2z + -100) + -20

Remove parenthesis around (50 + z)
-100 + 3z = 50 + z + (2z + -100) + -20

Reorder the terms:
-100 + 3z = 50 + z + (-100 + 2z) + -20

Remove parenthesis around (-100 + 2z)
-100 + 3z = 50 + z + -100 + 2z + -20

Reorder the terms:
-100 + 3z = 50 + -100 + -20 + z + 2z

Combine like terms: 50 + -100 = -50
-100 + 3z = -50 + -20 + z + 2z

Combine like terms: -50 + -20 = -70
-100 + 3z = -70 + z + 2z

Combine like terms: z + 2z = 3z
-100 + 3z = -70 + 3z

Add '-3z' to each side of the equation.
-100 + 3z + -3z = -70 + 3z + -3z

Combine like terms: 3z + -3z = 0
-100 + 0 = -70 + 3z + -3z
-100 = -70 + 3z + -3z

Combine like terms: 3z + -3z = 0
-100 = -70 + 0
-100 = -70

Solving
-100 = -70

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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