(2z-4)*5=(2z+7)*6

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Solution for (2z-4)*5=(2z+7)*6 equation: 



(2z-4)*5=(2z+7)*6

We move all terms to the left:

(2z-4)*5-((2z+7)*6)=0

We multiply parentheses

10z-((2z+7)*6)-20=0



We calculate terms in parentheses: -((2z+7)*6), so:

(2z+7)*6

We multiply parentheses

12z+42

Back to the equation:

-(12z+42)



We get rid of parentheses

10z-12z-42-20=0

We add all the numbers together, and all the variables

-2z-62=0

We move all terms containing z to the left, all other terms to the right

-2z=62

z=62/-2

z=-31

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