(2z-5)=5(z+2)

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Solution for (2z-5)=5(z+2) equation:


Simplifying
(2z + -5) = 5(z + 2)

Reorder the terms:
(-5 + 2z) = 5(z + 2)

Remove parenthesis around (-5 + 2z)
-5 + 2z = 5(z + 2)

Reorder the terms:
-5 + 2z = 5(2 + z)
-5 + 2z = (2 * 5 + z * 5)
-5 + 2z = (10 + 5z)

Solving
-5 + 2z = 10 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
-5 + 2z + -5z = 10 + 5z + -5z

Combine like terms: 2z + -5z = -3z
-5 + -3z = 10 + 5z + -5z

Combine like terms: 5z + -5z = 0
-5 + -3z = 10 + 0
-5 + -3z = 10

Add '5' to each side of the equation.
-5 + 5 + -3z = 10 + 5

Combine like terms: -5 + 5 = 0
0 + -3z = 10 + 5
-3z = 10 + 5

Combine like terms: 10 + 5 = 15
-3z = 15

Divide each side by '-3'.
z = -5

Simplifying
z = -5

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