(2z-7)(3)=33

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Solution for (2z-7)(3)=33 equation: 



(2z-7)(3)=33

We move all terms to the left:

(2z-7)(3)-(33)=0

We multiply parentheses

6z-21-33=0

We add all the numbers together, and all the variables

6z-54=0

We move all terms containing z to the left, all other terms to the right

6z=54

z=54/6

z=9

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