(2z/5)-((4z-3)/10)=(-z+1)/10

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Solution for (2z/5)-((4z-3)/10)=(-z+1)/10 equation: 


z in (-oo:+oo)

(2*z)/5-((4*z-3)/10) = (1-z)/10 // - (1-z)/10

(2*z)/5-((4*z-3)/10)-((1-z)/10) = 0

(-1*(4*z-3))/10+(-1*(1-z))/10+(2*z)/5 = 0

(-1*5*(4*z-3))/(5*10)+(-1*5*(1-z))/(5*10)+(2*10*z)/(5*10) = 0

2*10*z-1*5*(4*z-3)-1*5*(1-z) = 0

20*z-15*z+10 = 0

5*z+10 = 0

(5*z+10)/(5*10) = 0

(5*z+10)/(5*10) = 0 // * 5*10

5*z+10 = 0

5*z+10 = 0 // - 10

5*z = -10 // : 5

z = -10/5

z = -2

z = -2

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