(2z/5)-(4z-3/10)=-z+1/10

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Solution for (2z/5)-(4z-3/10)=-z+1/10 equation: 


z in (-oo:+oo)

(2*z)/5-(4*z)+3/10 = 1/10-z // - 1/10-z

(2*z)/5-(4*z)+z+3/10-(1/10) = 0

(2*z)/5-4*z+z+3/10-1/10 = 0

1/5-13/5*z = 0 // - 1/5

-13/5*z = -1/5 // : -13/5

z = -1/5/(-13/5)

z = 1/13

z = 1/13

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