(2z/z+2)-(3z/2z-3)

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Solution for (2z/z+2)-(3z/2z-3) equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

(2*z)/z-(((3*z)/2)*z)+2+3 = 0

(-3/2)*z^2+(2*z)/z+2+3 = 0

-3/2*z^2 = -7 // : -3/2

z^2 = 14/3

z^2 = 14/3 // ^ 1/2

abs(z) = (14/3)^(1/2)

z = (14/3)^(1/2) or z = -(14/3)^(1/2)

z in { (14/3)^(1/2), -(14/3)^(1/2) }

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