(2z=7)(3)=33

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Solution for (2z=7)(3)=33 equation: 



(2z=7)(3)=33

We move all terms to the left:

(2z-(7)(3))=0

We get rid of parentheses

2z-73=0

We move all terms containing z to the left, all other terms to the right

2z=73

z=73/2

z=36+1/2

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