(3(2-z))/5=z

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Solution for (3(2-z))/5=z equation: 



(3(2-z))/5=z

We move all terms to the left:

(3(2-z))/5-(z)=0

We add all the numbers together, and all the variables

(3(-1z+2))/5-z=0

We add all the numbers together, and all the variables

-1z+(3(-1z+2))/5=0

We multiply all the terms by the denominator


-1z*5+(3(-1z+2))=0



We calculate terms in parentheses: +(3(-1z+2)), so:

3(-1z+2)

We multiply parentheses

-3z+6

Back to the equation:

+(-3z+6)



Wy multiply elements

-5z+(-3z+6)=0

We get rid of parentheses

-5z-3z+6=0

We add all the numbers together, and all the variables

-8z+6=0

We move all terms containing z to the left, all other terms to the right

-8z=-6

z=-6/-8

z=3/4

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