(3(2x+1)/5)=2x-5

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Solution for (3(2x+1)/5)=2x-5 equation: 



(3(2x+1)/5)=2x-5

We move all terms to the left:

(3(2x+1)/5)-(2x-5)=0

We get rid of parentheses

(3(2x+1)/5)-2x+5=0

We multiply all the terms by the denominator


(3(2x+1)-2x*5)+5*5)=0



We calculate terms in parentheses: +(3(2x+1)-2x*5), so:

3(2x+1)-2x*5

We multiply parentheses

6x-2x*5+3

Wy multiply elements

6x-10x+3

We add all the numbers together, and all the variables

-4x+3

Back to the equation:

+(-4x+3)



We add all the numbers together, and all the variables

(-4x+3)=0

We get rid of parentheses

-4x+3=0

We move all terms containing x to the left, all other terms to the right

-4x=-3

x=-3/-4

x=3/4

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