(3(2x-1))/5+1=10

Solution for (3(2x-1))/5+1=10 equation:

(3(2x-1))/5+1=10

We move all terms to the left:

(3(2x-1))/5+1-(10)=0

We add all the numbers together, and all the variables

(3(2x-1))/5-9=0

We multiply all the terms by the denominator


(3(2x-1))-9*5=0


We calculate terms in parentheses: +(3(2x-1)), so:

3(2x-1)

We multiply parentheses

6x-3

Back to the equation:

+(6x-3)


We add all the numbers together, and all the variables

(6x-3)-45=0

We get rid of parentheses

6x-3-45=0

We add all the numbers together, and all the variables

6x-48=0

We move all terms containing x to the left, all other terms to the right

6x=48

x=48/6

x=8