(3(35)+5)=(35+3y)

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Solution for (3(35)+5)=(35+3y) equation: 



(3(35)+5)=(35+3y)

We move all terms to the left:

(3(35)+5)-((35+3y))=0

We add all the numbers together, and all the variables

-((3y+35))+340=0



We calculate terms in parentheses: -((3y+35)), so:

(3y+35)

We get rid of parentheses

3y+35

Back to the equation:

-(3y+35)



We get rid of parentheses

-3y-35+340=0

We add all the numbers together, and all the variables

-3y+305=0

We move all terms containing y to the left, all other terms to the right

-3y=-305

y=-305/-3

y=101+2/3

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