(3(4x-5)=6x+15)

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Solution for (3(4x-5)=6x+15) equation: 



(3(4x-5)=6x+15)

We move all terms to the left:

(3(4x-5)-(6x+15))=0



We calculate terms in parentheses: +(3(4x-5)-(6x+15)), so:

3(4x-5)-(6x+15)

We multiply parentheses

12x-(6x+15)-15

We get rid of parentheses

12x-6x-15-15

We add all the numbers together, and all the variables

6x-30

Back to the equation:

+(6x-30)



We get rid of parentheses

6x-30=0

We move all terms containing x to the left, all other terms to the right

6x=30

x=30/6

x=5

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