(3(b+2))/2=(4b-10)/4

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Solution for (3(b+2))/2=(4b-10)/4 equation: 



(3(b+2))/2=(4b-10)/4

We move all terms to the left:

(3(b+2))/2-((4b-10)/4)=0

We calculate fractions


12b/()+(-((4b-10)*2)/()=0



We calculate terms in parentheses: +(-((4b-10)*2)/(), so:

-((4b-10)*2)/(

We multiply all the terms by the denominator


-((4b-10)*2)



We calculate terms in parentheses: -((4b-10)*2), so:

(4b-10)*2

We multiply parentheses

8b-20

Back to the equation:

-(8b-20)



We get rid of parentheses

-8b+20

Back to the equation:

+(-8b+20)



We get rid of parentheses

12b/()-8b+20=0

We multiply all the terms by the denominator


12b-8b*()+20*()=0

We add all the numbers together, and all the variables

12b-8b*()=0

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