(3(c+4)/2)-4=11

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Solution for (3(c+4)/2)-4=11 equation: 



(3(c+4)/2)-4=11

We move all terms to the left:

(3(c+4)/2)-4-(11)=0

We add all the numbers together, and all the variables

(3(c+4)/2)-15=0

We multiply all the terms by the denominator


(3(c+4)-15*2)=0



We calculate terms in parentheses: +(3(c+4)-15*2), so:

3(c+4)-15*2

We add all the numbers together, and all the variables

3(c+4)-30

We multiply parentheses

3c+12-30

We add all the numbers together, and all the variables

3c-18

Back to the equation:

+(3c-18)



We get rid of parentheses

3c-18=0

We move all terms containing c to the left, all other terms to the right

3c=18

c=18/3

c=6

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