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(3(x+1))/4=2x-3
We move all terms to the left:
(3(x+1))/4-(2x-3)=0
We get rid of parentheses
(3(x+1))/4-2x+3=0
We multiply all the terms by the denominator
(3(x+1))-2x*4+3*4=0
We calculate terms in parentheses: +(3(x+1)), so:We add all the numbers together, and all the variables
3(x+1)
We multiply parentheses
3x+3
Back to the equation:
+(3x+3)
(3x+3)-2x*4+12=0
Wy multiply elements
(3x+3)-8x+12=0
We get rid of parentheses
3x-8x+3+12=0
We add all the numbers together, and all the variables
-5x+15=0
We move all terms containing x to the left, all other terms to the right
-5x=-15
x=-15/-5
x=+3
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