(3(x+1)/6)=2x-4

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Solution for (3(x+1)/6)=2x-4 equation: 



(3(x+1)/6)=2x-4

We move all terms to the left:

(3(x+1)/6)-(2x-4)=0

We get rid of parentheses

(3(x+1)/6)-2x+4=0

We multiply all the terms by the denominator


(3(x+1)-2x*6)+4*6)=0



We calculate terms in parentheses: +(3(x+1)-2x*6), so:

3(x+1)-2x*6

We multiply parentheses

3x-2x*6+3

Wy multiply elements

3x-12x+3

We add all the numbers together, and all the variables

-9x+3

Back to the equation:

+(-9x+3)



We add all the numbers together, and all the variables

(-9x+3)=0

We get rid of parentheses

-9x+3=0

We move all terms containing x to the left, all other terms to the right

-9x=-3

x=-3/-9

x=1/3

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