(3(x+4)/7)=2x-3

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Solution for (3(x+4)/7)=2x-3 equation: 


x in (-oo:+oo)

(3*(x+4))/7 = 2*x-3 // - 2*x-3

(3*(x+4))/7-(2*x)+3 = 0

(3*(x+4))/7-2*x+3 = 0

(3*(x+4))/7+(-2*7*x)/7+(3*7)/7 = 0

3*(x+4)-2*7*x+3*7 = 0

12-11*x+21 = 0

33-11*x = 0

(33-11*x)/7 = 0

(33-11*x)/7 = 0 // * 7

33-11*x = 0

33-11*x = 0 // - 33

-11*x = -33 // : -11

x = -33/(-11)

x = 3

x = 3

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