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(3(x+5))/4=2x-5
We move all terms to the left:
(3(x+5))/4-(2x-5)=0
We get rid of parentheses
(3(x+5))/4-2x+5=0
We multiply all the terms by the denominator
(3(x+5))-2x*4+5*4=0
We calculate terms in parentheses: +(3(x+5)), so:We add all the numbers together, and all the variables
3(x+5)
We multiply parentheses
3x+15
Back to the equation:
+(3x+15)
(3x+15)-2x*4+20=0
Wy multiply elements
(3x+15)-8x+20=0
We get rid of parentheses
3x-8x+15+20=0
We add all the numbers together, and all the variables
-5x+35=0
We move all terms containing x to the left, all other terms to the right
-5x=-35
x=-35/-5
x=+7
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