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(3(x+7)/2=19
We move all terms to the left:
(3(x+7)/2-(19)=0
We multiply all the terms by the denominator
(3(x+7)=0
We calculate terms in parentheses: +(3(x+7), so:
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| -3t+10=-8-t | | f+5=89 | | 0,80=√(x/20) | | -20=r-99 | | x=33x^2-21/3x=0 | | (x+5)(x+2)=44 | | 2(x+5)=3(1+x0 | | q+71=9 | | f-92=-19 | | X=14|(7+7x)-(4+5x) | | 17^(7x)=6^(-x-9) | | t+10=99 | | m-84=-37 | | 3(7^x)-2=124 | | 4+3k=–3k+10k= | | 5/x-6=7x | | 4(m-3)=2(6-2m) | | C(k)=35,35 | | -13=d-14 | | 8u+36=180 | | 2(5)^(2x+1)+4=18 | | 20c+180=80 | | 106=8(5+n)+3n | | 7p+180=124 | | -2=n+-10 | | 5x=3x20 | | 3m-25-8m=m-14 | | 16a+180=116 | | 72x-504=288 | | 4.1+10m=7.34 | | 16c+36=180 | | p+-9=35 |