(3(y-2))/5=1-3y

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Solution for (3(y-2))/5=1-3y equation: 


y in (-oo:+oo)

(3*(y-2))/5 = 1-(3*y) // - 1-(3*y)

(3*(y-2))/5+3*y-1 = 0

(3*(y-2))/5+(3*5*y)/5+(-1*5)/5 = 0

3*(y-2)+3*5*y-1*5 = 0

18*y-6-5 = 0

18*y-11 = 0

(18*y-11)/5 = 0

(18*y-11)/5 = 0 // * 5

18*y-11 = 0

18*y-11 = 0 // + 11

18*y = 11 // : 18

y = 11/18

y = 11/18

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