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(3)/(2)(d+12)=(1)/(2)(2d-6)
We move all terms to the left:
(3)/(2)(d+12)-((1)/(2)(2d-6))=0
Domain of the equation: 2(d+12)!=0
d∈R
Domain of the equation: 2(2d-6))!=0We calculate fractions
d∈R
(6d2/(2(d+12)*2(2d-6)))+(-2dd/(2(d+12)*2(2d-6)))=0
We calculate terms in parentheses: +(6d2/(2(d+12)*2(2d-6))), so:
6d2/(2(d+12)*2(2d-6))
We multiply all the terms by the denominator
6d2
We add all the numbers together, and all the variables
6d^2
Back to the equation:
+(6d^2)
We calculate terms in parentheses: +(-2dd/(2(d+12)*2(2d-6))), so:We get rid of parentheses
-2dd/(2(d+12)*2(2d-6))
We multiply all the terms by the denominator
-2dd
Back to the equation:
+(-2dd)
6d^2-2dd=0
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