(3)/(2)(x+4)=2-(1)/(5)(1-4x)

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Solution for (3)/(2)(x+4)=2-(1)/(5)(1-4x) equation:



(3)/(2)(x+4)=2-(1)/(5)(1-4x)
We move all terms to the left:
(3)/(2)(x+4)-(2-(1)/(5)(1-4x))=0
Domain of the equation: 2(x+4)!=0
x∈R
Domain of the equation: 5(1-4x))!=0
x∈R
We add all the numbers together, and all the variables
3/2(x+4)-(2-1/5(-4x+1))=0
We calculate fractions
(15x(-)/(2(x+4)*5(-4x+1)))+(-(-2xx)/(2(x+4)*5(-4x+1)))=0
We calculate terms in parentheses: +(15x(-)/(2(x+4)*5(-4x+1))), so:
15x(-)/(2(x+4)*5(-4x+1))
We add all the numbers together, and all the variables
15x0/(2(x+4)*5(-4x+1))
We multiply all the terms by the denominator
15x0
We add all the numbers together, and all the variables
15x
Back to the equation:
+(15x)
We calculate terms in parentheses: +(-(-2xx)/(2(x+4)*5(-4x+1))), so:
-(-2xx)/(2(x+4)*5(-4x+1))
We multiply all the terms by the denominator
-(-2xx)
We get rid of parentheses
2xx
Back to the equation:
+(2xx)

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