(3)/(2x)-(1)/(2(x+10))=1

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Solution for (3)/(2x)-(1)/(2(x+10))=1 equation: 



(3)/(2x)-(1)/(2(x+10))=1

We move all terms to the left:

(3)/(2x)-(1)/(2(x+10))-(1)=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R





Domain of the equation: (2(x+10))!=0

x∈R



We calculate fractions


(3*(2(x+10)))/(2x*(2(x+10)))+(-2x)/(2x*(2(x+10)))-1=0



We calculate terms in parentheses: +(3*(2(x+10)))/(2x*(2(x+10))), so:

3*(2(x+10)))/(2x*(2(x+10))

We multiply all the terms by the denominator


3*(2(x+10)))

Back to the equation:

+(3*(2(x+10))))





We calculate terms in parentheses: +(-2x)/(2x*(2(x+10))), so:

-2x)/(2x*(2(x+10))

We multiply all the terms by the denominator


-2x)

Back to the equation:

+(-2x))

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