(3)/(4)(20x+24)-10=-(1)/(5)(45x-45)

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Solution for (3)/(4)(20x+24)-10=-(1)/(5)(45x-45) equation: 



(3)/(4)(20x+24)-10=-(1)/(5)(45x-45)

We move all terms to the left:

(3)/(4)(20x+24)-10-(-(1)/(5)(45x-45))=0



Domain of the equation: 4(20x+24)!=0

x∈R





Domain of the equation: 5(45x-45))!=0

x∈R



We calculate fractions


(15x4/(4(20x+24)*5(45x-45)))+(-(-4x2)/(4(20x+24)*5(45x-45)))-10=0



We calculate terms in parentheses: +(15x4/(4(20x+24)*5(45x-45))), so:

15x4/(4(20x+24)*5(45x-45))

We multiply all the terms by the denominator


15x4

We add all the numbers together, and all the variables

15x^4

We do not support expression: x^4

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