(3)/(4)(6x+1)-3x=(1)/(4)(2x-1)

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Solution for (3)/(4)(6x+1)-3x=(1)/(4)(2x-1) equation: 



(3)/(4)(6x+1)-3x=(1)/(4)(2x-1)

We move all terms to the left:

(3)/(4)(6x+1)-3x-((1)/(4)(2x-1))=0



Domain of the equation: 4(6x+1)!=0

x∈R





Domain of the equation: 4(2x-1))!=0

x∈R



We add all the numbers together, and all the variables

-3x+3/4(6x+1)-(1/4(2x-1))=0

We calculate fractions


-3x+(12x2/(4(6x+1)*4(2x-1)))+(-4x6/(4(6x+1)*4(2x-1)))=0



We calculate terms in parentheses: +(12x2/(4(6x+1)*4(2x-1))), so:

12x2/(4(6x+1)*4(2x-1))

We multiply all the terms by the denominator


12x2

We add all the numbers together, and all the variables

12x^2

Back to the equation:

+(12x^2)





We calculate terms in parentheses: +(-4x6/(4(6x+1)*4(2x-1))), so:

-4x6/(4(6x+1)*4(2x-1))

We multiply all the terms by the denominator


-4x6

We add all the numbers together, and all the variables

-4x^6

We do not support expression: x^6

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