(3)/(4)n-18=(1)/(4)n-4

Solution for (3)/(4)n-18=(1)/(4)n-4 equation:

(3)/(4)n-18=(1)/(4)n-4

We move all terms to the left:

(3)/(4)n-18-((1)/(4)n-4)=0


Domain of the equation: 4n!=0

n!=0/4

n!=0

n∈R



Domain of the equation: 4n-4)!=0

n∈R


We get rid of parentheses

3/4n-1/4n+4-18=0

We multiply all the terms by the denominator


4*4n-18*4n+3-1=0

We add all the numbers together, and all the variables

4*4n-18*4n+2=0

Wy multiply elements

16n-72n+2=0

We add all the numbers together, and all the variables

-56n+2=0

We move all terms containing n to the left, all other terms to the right

-56n=-2

n=-2/-56

n=1/28