(3)/(4)y+2-(1)/(2)y=6

Solution for (3)/(4)y+2-(1)/(2)y=6 equation:

(3)/(4)y+2-(1)/(2)y=6

We move all terms to the left:

(3)/(4)y+2-(1)/(2)y-(6)=0


Domain of the equation: 4y!=0

y!=0/4

y!=0

y∈R



Domain of the equation: 2y!=0

y!=0/2

y!=0

y∈R


We add all the numbers together, and all the variables

3/4y-1/2y-4=0

We calculate fractions


6y/8y^2+(-4y)/8y^2-4=0

We multiply all the terms by the denominator


6y+(-4y)-4*8y^2=0

Wy multiply elements

-32y^2+6y+(-4y)=0

We get rid of parentheses

-32y^2+6y-4y=0

We add all the numbers together, and all the variables

-32y^2+2y=0

a = -32; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-32)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-32}=\frac{-4}{-64}
=1/16
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-32}=\frac{0}{-64}
=0
$