(3)/(4n-1)=(2)/(2n-5)

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Solution for (3)/(4n-1)=(2)/(2n-5) equation: 


D( n )

2*n-5 = 0

4*n-1 = 0

2*n-5 = 0

2*n-5 = 0

2*n-5 = 0 // + 5

2*n = 5 // : 2

n = 5/2

4*n-1 = 0

4*n-1 = 0

4*n-1 = 0 // + 1

4*n = 1 // : 4

n = 1/4

n in (-oo:1/4) U (1/4:5/2) U (5/2:+oo)

3/(4*n-1) = 2/(2*n-5) // - 2/(2*n-5)

3/(4*n-1)-(2/(2*n-5)) = 0

3/(4*n-1)-2*(2*n-5)^-1 = 0

3/(4*n-1)-2/(2*n-5) = 0

(3*(2*n-5))/((4*n-1)*(2*n-5))+(-2*(4*n-1))/((4*n-1)*(2*n-5)) = 0

3*(2*n-5)-2*(4*n-1) = 0

-2*n-13 = 0

(-2*n-13)/((4*n-1)*(2*n-5)) = 0

(-2*n-13)/((4*n-1)*(2*n-5)) = 0 // * (4*n-1)*(2*n-5)

-2*n-13 = 0

-2*n-13 = 0 // + 13

-2*n = 13 // : -2

n = 13/(-2)

n = -13/2

n = -13/2

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