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(3)/(4x-5)=x
We move all terms to the left:
(3)/(4x-5)-(x)=0
Domain of the equation: (4x-5)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
4x!=5
x!=5/4
x!=1+1/4
x∈R
-1x+3/(4x-5)=0
We multiply all the terms by the denominator
-1x*(4x-5)+3=0
We multiply parentheses
-4x^2+5x+3=0
a = -4; b = 5; c = +3;
Δ = b2-4ac
Δ = 52-4·(-4)·3
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{73}}{2*-4}=\frac{-5-\sqrt{73}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{73}}{2*-4}=\frac{-5+\sqrt{73}}{-8} $
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