(3)/(5)f+24=4-(1)/(5)f

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Solution for (3)/(5)f+24=4-(1)/(5)f equation:



(3)/(5)f+24=4-(1)/(5)f
We move all terms to the left:
(3)/(5)f+24-(4-(1)/(5)f)=0
Domain of the equation: 5f!=0
f!=0/5
f!=0
f∈R
Domain of the equation: 5f)!=0
f!=0/1
f!=0
f∈R
We add all the numbers together, and all the variables
3/5f-(-1/5f+4)+24=0
We get rid of parentheses
3/5f+1/5f-4+24=0
We multiply all the terms by the denominator
-4*5f+24*5f+3+1=0
We add all the numbers together, and all the variables
-4*5f+24*5f+4=0
Wy multiply elements
-20f+120f+4=0
We add all the numbers together, and all the variables
100f+4=0
We move all terms containing f to the left, all other terms to the right
100f=-4
f=-4/100
f=-1/25

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