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(3)/(5)x=96
We move all terms to the left:
(3)/(5)x-(96)=0
Domain of the equation: 5x!=0We multiply all the terms by the denominator
x!=0/5
x!=0
x∈R
-96*5x+3=0
Wy multiply elements
-480x+3=0
We move all terms containing x to the left, all other terms to the right
-480x=-3
x=-3/-480
x=1/160
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