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(3)/(8)y-5=(5)/(8)y-3
We move all terms to the left:
(3)/(8)y-5-((5)/(8)y-3)=0
Domain of the equation: 8y!=0
y!=0/8
y!=0
y∈R
Domain of the equation: 8y-3)!=0We get rid of parentheses
y∈R
3/8y-5/8y+3-5=0
We multiply all the terms by the denominator
3*8y-5*8y+3-5=0
We add all the numbers together, and all the variables
3*8y-5*8y-2=0
Wy multiply elements
24y-40y-2=0
We add all the numbers together, and all the variables
-16y-2=0
We move all terms containing y to the left, all other terms to the right
-16y=2
y=2/-16
y=-1/8
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