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(3)/(x)=(15)/(8x)+3
We move all terms to the left:
(3)/(x)-((15)/(8x)+3)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 8x+3)!=0We get rid of parentheses
x∈R
3/x-15/8x-3=0
We calculate fractions
24x/8x^2+(-15x)/8x^2-3=0
We multiply all the terms by the denominator
24x+(-15x)-3*8x^2=0
Wy multiply elements
-24x^2+24x+(-15x)=0
We get rid of parentheses
-24x^2+24x-15x=0
We add all the numbers together, and all the variables
-24x^2+9x=0
a = -24; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-24)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-24}=\frac{-18}{-48} =3/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-24}=\frac{0}{-48} =0 $
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